Related
Shubham Chhabra: I'm passing a pointer to a function with the intention of modifying the data held at the original address. #include<bits/stdc++.h>
using namespace std;
void square(int **x)
{
**x = **x + 2;
cout<<**x<<" ";
}
int main()
{
int y = 5;
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Frank 26 I read all the answer questions on this topic and none of them answer my question... I'm still reading about pointers in C, and now I'm trying to understand how to pass pointers through functions. However, the following code (taken from tutorialspoint
Shubham Chhabra: I'm passing a pointer to a function with the intention of modifying the data held at the original address. #include<bits/stdc++.h>
using namespace std;
void square(int **x)
{
**x = **x + 2;
cout<<**x<<" ";
}
int main()
{
int y = 5;
Macaque In the function declaration below, the first parameter is a String, specifically an array of chars, and the third parameter is a pointer to an integer. Is the second parameter a pointer to an array of characters? In other words, a pointer to a pointer?
N08 In an effort to optimize my code below, it seems to me that it would be beneficial if I could pass a pointer to one of the member functions str1and str2pass it as a parameter fill_vecwithout having to do two explicit loops fill_vec. Is there a preferred wa
username I just want to assign one pointer to another through a function (same memory address). My code is as follows: #include <stdio.h>
void d(int** a)
{
int* val_ptr = malloc(1);
*val_ptr = 5;
printf("%d\n", *val_ptr);
a = &val_ptr;
}
i
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];
Pavigilti Here I have defined two function pointers func1and func2, which I guess is a way to use function pointers in c. But my problem is when I call executor(func1);
executor(func2);
How do I allocate memory uint8_t *and pass it as an argument to either fu
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Frank 26 I read all the answer questions on this topic and none of them answer my question... I'm still reading about pointers in C, and now I'm trying to understand how to pass pointers through functions. However, the following code (taken from tutorialspoint
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];
Nejat Here I read an article about when to pass a pointer as a function parameter. But I'm wondering about some cases where you should pass a pointer to a pointer as a parameter to a function. To be more clear, I'd like to know when I should use something like
Macaque In the function declaration below, the first parameter is a String, specifically an array of chars, and the third parameter is a pointer to an integer. Is the second parameter a pointer to an array of characters? In other words, a pointer to a pointer?
Li Bo I am new to learning c.....so I am trying to create a tree structure from an input like this: (2, 50) (4, 30) (9, 30) (10, 400) (-5, -40)
(7, 20) (19, 200) (20, 50) (-18, -200) (-2, 29)
(2, 67) (4, 35) (9, 45) (-18, 100)
First, I define some data struc
Macaque In the function declaration below, the first parameter is a String, specifically an array of chars, and the third parameter is a pointer to an integer. Is the second parameter a pointer to an array of characters? In other words, a pointer to a pointer?
unlimited This item table prints different permutations of strings. If I declare the string as a char array in main and pass the array name in the printAnagram function it works fine. But if I declare string as char *s="hello" and pass 's' it crashes. Why? #in
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Frank 26 I read all the answer questions on this topic and none of them answer my question... I'm still reading about pointers in C, and now I'm trying to understand how to pass pointers through functions. However, the following code (taken from tutorialspoint
Frank 26 I read all the answer questions on this topic and none of them answer my question... I'm still reading about pointers in C, and now I'm trying to understand how to pass pointers through functions. However, the following code (taken from tutorialspoint
unlimited This item table prints different permutations of strings. If I declare the string as a char array in main and pass the array name in the printAnagram function it works fine. But if I declare string as char *s="hello" and pass 's' it crashes. Why? #in
Macaque In the function declaration below, the first parameter is a String, specifically an array of chars, and the third parameter is a pointer to an integer. Is the second parameter a pointer to an array of characters? In other words, a pointer to a pointer?
username I just want to assign one pointer to another through a function (same memory address). My code is as follows: #include <stdio.h>
void d(int** a)
{
int* val_ptr = malloc(1);
*val_ptr = 5;
printf("%d\n", *val_ptr);
a = &val_ptr;
}
i