Related
Macaque In the function declaration below, the first parameter is a String, specifically an array of chars, and the third parameter is a pointer to an integer. Is the second parameter a pointer to an array of characters? In other words, a pointer to a pointer?
Macaque In the function declaration below, the first parameter is a String, specifically an array of chars, and the third parameter is a pointer to an integer. Is the second parameter a pointer to an array of characters? In other words, a pointer to a pointer?
Macaque In the function declaration below, the first parameter is a String, specifically an array of chars, and the third parameter is a pointer to an integer. Is the second parameter a pointer to an array of characters? In other words, a pointer to a pointer?
unlimited This item table prints different permutations of strings. If I declare the string as a char array in main and pass the array name in the printAnagram function it works fine. But if I declare string as char *s="hello" and pass 's' it crashes. Why? #in
unlimited This item table prints different permutations of strings. If I declare the string as a char array in main and pass the array name in the printAnagram function it works fine. But if I declare string as char *s="hello" and pass 's' it crashes. Why? #in
but Some background; I have to connect an EEprom that has an I2C interface. I want to save an array of floats in memory and then read it back. I want to make it asap. Currently, I have the following solution for this, which works great. float a[5];
unsigned ch
bob jane Below is my function that takes a char array of size 2, passes it to the function, and the function should return the same 2 chars (it's a bit complicated when it comes to communicating with hardware devices). The problem is when I pass char(*in)[2] t
open I'm trying to understand more about char pointers in C, but one thing got me. Suppose I want to pass a char pointer to a function and change the value represented by that pointer. Here is an example: int Foo (char *(&Msg1), char* Msg2, char* Msg3){
ch
open I'm trying to understand more about char pointers in C, but one thing got me. Suppose I want to pass a char pointer to a function and change the value represented by that pointer. Here is an example: int Foo (char *(&Msg1), char* Msg2, char* Msg3){
ch
tiktak I am trying to get the mac address with the following code: void getMacAdress(unsigned char **address)
{
int s;
struct ifreq buffer;
s = socket(PF_INET, SOCK_DGRAM, 0);
memset(&buffer, 0x00, sizeof(buffer));
strcpy(buffer.ifr_name,
tiktak I am trying to get the mac address with the following code: void getMacAdress(unsigned char **address)
{
int s;
struct ifreq buffer;
s = socket(PF_INET, SOCK_DGRAM, 0);
memset(&buffer, 0x00, sizeof(buffer));
strcpy(buffer.ifr_name,
tiktak I am trying to get the mac address with the following code: void getMacAdress(unsigned char **address)
{
int s;
struct ifreq buffer;
s = socket(PF_INET, SOCK_DGRAM, 0);
memset(&buffer, 0x00, sizeof(buffer));
strcpy(buffer.ifr_name,
Bruno Ely In C, why can I pass a character array to a function that takes a char *as a parameter, but not the address of the array to a function that takes a char **? UPDATE: Interestingly, changing the parameter type char* qux[12]to does n't completely change
Bruno Ely In C, why can I pass a character array to a function that takes a char *as a parameter, but not the address of the array to a function that takes a char **? UPDATE: Interestingly, changing the parameter type char* qux[12]to does n't completely change
Bruno Ely In C, why can I pass a character array to a function that takes a char *as a parameter, but not the address of the array to a function that takes a char **? UPDATE: Interestingly, changing the parameter type char* qux[12]to does n't completely change
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Frank 26 I read all the answer questions on this topic and none of them answer my question... I'm still reading about pointers in C, and now I'm trying to understand how to pass pointers through functions. However, the following code (taken from tutorialspoint
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Frank 26 I read all the answer questions on this topic and none of them answer my question... I'm still reading about pointers in C, and now I'm trying to understand how to pass pointers through functions. However, the following code (taken from tutorialspoint
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Zach I come across the following code: int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}
I don't understand the purpose of (int*)the end of the first argument ? I'm Uncover the mystery: int (*progress_fn)(int*)
It can be explained as follows: int (*pro
Frank 26 I read all the answer questions on this topic and none of them answer my question... I'm still reading about pointers in C, and now I'm trying to understand how to pass pointers through functions. However, the following code (taken from tutorialspoint
Frank 26 I read all the answer questions on this topic and none of them answer my question... I'm still reading about pointers in C, and now I'm trying to understand how to pass pointers through functions. However, the following code (taken from tutorialspoint
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];
12th place I'm having trouble passing an array of integers as a reference and then modifying the original array. #include <stdio.h>
// sets the 2 element of i to 5
void setToFive(int *i[10]){
*i[2] = 5;
printf("hello\n");
}
int main(){
int i[10];