Related
List if i have two lists l1 = [ 'A', 'B' ]
l2 = [ 1, 2 ]
What is the most elegant way to get a pandas dataframe like this: +-----+-----+-----+
| | l1 | l2 |
+-----+-----+-----+
| 0 | A | 1 |
+-----+-----+-----+
| 1 | A | 2 |
+-----+-----+--
Esostack Right now I'm trying to write a function that takes an array and an integer n and gives a list of each combination of size n (i.e. a list of int arrays). I could write it using n nested loops, but that only works for a subset of a certain size. I don'
GhostKU I'm not sure my question is correct, but I don't know how to explain it. So I have something like a = ['11', '12']
b = ['21', '22']
c = ['31', '32']
And I need to get something like: result = [
['11', '21', '31'],
['11', '21', '32'],
['11'
Egvin Seday This is related to this question , but I also want the corresponding one's complement sorted list with elements that are not efficiently selected using python or c++ . For example, for an ordered list, list=(0,1,1,2,3,3)when we select 3 elements, o
Chinnon I am using python 2.7, I have the following list: new_out_filename = ['OFF_B8', 0, 'ON_B8', 1, 'ON_B16', 4, 'OFF_B0', 7]
I want to get all combinations of strings like this OFF_B8_vs_ON_B8, OFF_B8_vs_ON_B16, OFF_B8_vs_OFf_B0, ON_B8_vs_ON_16, etc. Is t
Esostack Right now, I'm trying to write a function that takes an array and an integer n, and gives a list of each combination of size n (hence a list of int arrays). I could write it using n nested loops, but that only works for a subset of a certain size. I c
Robert Tiger Say I have this list of lists: lst_of_lsts = [['1-1', '1-2', '1-3'], ['2-1', '2-2', '2-3'], ['3-1', '3-2', '3-3']]
How do I iterate to output all my possible combinationslen(lst_of_lsts) Desired output: comb1 = ['1-1', '2-1', '3-1']
comb2 = ['1-2
Alex TL / DR Given X = {(A,B),(B,C),(D,E),(B,A),(C,B)}( Xone of set) How to filter the sub-tuple which shows a unique combination (rather than a unique combination) so that it Xbecomes{(A,B),(B,C),(D,E))} longer form Most combination/permutation problems here
Daniel Rollins I have a list of elements (I have 11 elements in my actual list, this is just an example): x <- c(1, 2, 3)
and want to split them into two lists (with all the entries), but I want to return all possible combinations of this list like: (1,2)(3)
Ghost Rider I have a list of lists where the variables in each inner list are paths to images. Usually each inner list is about 35 in length, and there are 9 such lists in one list. E.g [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20,
Wow So if I start with: x = [a, b, c]
y = [[a], [b], [c], [a,b], [b,c]]
How can I get all combinations xof elements from it y? It's just like: y = [ [[a, b], c], [[b,c], a], [a, b, c]
I've looked into itertools and list comprehensions but still struggling. A
Abbie i tried this import itertools
a=[10, 1 ,2, 7, 6, 1, 5]
b=[]
for i in range(len(a)):
for s in itertools.combinations(a,i):
if s not in b:
b.append(s)
print(b)
I am getting the desired output as a tuple. I would like the output as
List if i have two lists l1 = [ 'A', 'B' ]
l2 = [ 1, 2 ]
What is the most elegant way to get a pandas dataframe like this: +-----+-----+-----+
| | l1 | l2 |
+-----+-----+-----+
| 0 | A | 1 |
+-----+-----+-----+
| 1 | A | 2 |
+-----+-----+--
GhostKU I'm not sure my question is correct, but I don't know how to explain it. So I have something like a = ['11', '12']
b = ['21', '22']
c = ['31', '32']
And I need to get something like: result = [
['11', '21', '31'],
['11', '21', '32'],
['11'
GhostKU I'm not sure my question is correct, but I don't know how to explain it. So I have something like a = ['11', '12']
b = ['21', '22']
c = ['31', '32']
And I need to get something like: result = [
['11', '21', '31'],
['11', '21', '32'],
['11'
Chinnon I am using python 2.7, I have the following list: new_out_filename = ['OFF_B8', 0, 'ON_B8', 1, 'ON_B16', 4, 'OFF_B0', 7]
I want to get all combinations of strings like this OFF_B8_vs_ON_B8, OFF_B8_vs_ON_B16, OFF_B8_vs_OFf_B0, ON_B8_vs_ON_16, etc. Is t
Robert Tiger Say I have this list of lists: lst_of_lsts = [['1-1', '1-2', '1-3'], ['2-1', '2-2', '2-3'], ['3-1', '3-2', '3-3']]
How do I iterate to output all my possible combinationslen(lst_of_lsts) Desired output: comb1 = ['1-1', '2-1', '3-1']
comb2 = ['1-2
crepes I have a list:l = [1, (2, 3), (4, 5), 6] I want to select 3 items from this list, but only one item per sublist. Using combinationsI can achieve: Result = [[1, (2, 3), (4, 5)], [1, (2, 3), 6], [1, (4, 5), 6]] However, tuples do not expand. What's the mo
List if i have two lists l1 = [ 'A', 'B' ]
l2 = [ 1, 2 ]
What is the most elegant way to get a pandas dataframe like this: +-----+-----+-----+
| | l1 | l2 |
+-----+-----+-----+
| 0 | A | 1 |
+-----+-----+-----+
| 1 | A | 2 |
+-----+-----+--
Egvin Seday This is related to this question , but I also want the corresponding one's complement sorted list with elements that are not efficiently selected using python or c++ . For example, for an ordered list, list=(0,1,1,2,3,3)when we select 3 elements, o
Alex TL / DR Given X = {(A,B),(B,C),(D,E),(B,A),(C,B)}( Xone of set) How to filter the sub-tuple which shows a unique combination (rather than a unique combination) so that it Xbecomes{(A,B),(B,C),(D,E))} longer form Most combination/permutation problems here
List if i have two lists l1 = [ 'A', 'B' ]
l2 = [ 1, 2 ]
What is the most elegant way to get a pandas dataframe like this: +-----+-----+-----+
| | l1 | l2 |
+-----+-----+-----+
| 0 | A | 1 |
+-----+-----+-----+
| 1 | A | 2 |
+-----+-----+--
GhostKU I'm not sure my question is correct, but I don't know how to explain it. So I have something like a = ['11', '12']
b = ['21', '22']
c = ['31', '32']
And I need to get something like: result = [
['11', '21', '31'],
['11', '21', '32'],
['11'
Chinnon I am using python 2.7, I have the following list: new_out_filename = ['OFF_B8', 0, 'ON_B8', 1, 'ON_B16', 4, 'OFF_B0', 7]
I want to get all combinations of strings like this OFF_B8_vs_ON_B8, OFF_B8_vs_ON_B16, OFF_B8_vs_OFf_B0, ON_B8_vs_ON_16, etc. Is t
Robert Tiger Say I have this list of lists: lst_of_lsts = [['1-1', '1-2', '1-3'], ['2-1', '2-2', '2-3'], ['3-1', '3-2', '3-3']]
How do I iterate to output all my possible combinationslen(lst_of_lsts) Desired output: comb1 = ['1-1', '2-1', '3-1']
comb2 = ['1-2
Lizaveta I have some combinations of all pairs in a list: a = [1,2,3,4,5,6]
pairs = [pair for pair in itertools.combinations(a,2)]
print pairs
>>>[(1, 2), (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 4), (3, 5), (4, 5)]
How do I know what pairing I'm
Daniel Rollins I have a list of elements (I have 11 elements in my actual list, this is just an example): x <- c(1, 2, 3)
and want to split them into two lists (with all entries), but I want to return all possible combinations of this list like: (1,2)(3) & (1
Wow So if I start with: x = [a, b, c]
y = [[a], [b], [c], [a,b], [b,c]]
How can I get all combinations xof elements from it y? It's just like: y = [ [[a, b], c], [[b,c], a], [a, b, c]
I've looked into itertools and list comprehensions but still struggling. A
Alex TL / DR Given X = {(A,B),(B,C),(D,E),(B,A),(C,B)}( Xone of set) How to filter the sub-tuple which shows a unique combination (rather than a unique combination) so that it Xbecomes{(A,B),(B,C),(D,E))} longer form Most combination/permutation problems here