Related
Daniel Rollins I have a list of elements (I have 11 elements in my actual list, this is just an example): x <- c(1, 2, 3)
and want to split them into two lists (with all the entries), but I want to return all possible combinations of this list like: (1,2)(3)
List if i have two lists l1 = [ 'A', 'B' ]
l2 = [ 1, 2 ]
What is the most elegant way to get a pandas dataframe like this: +-----+-----+-----+
| | l1 | l2 |
+-----+-----+-----+
| 0 | A | 1 |
+-----+-----+-----+
| 1 | A | 2 |
+-----+-----+--
List if i have two lists l1 = [ 'A', 'B' ]
l2 = [ 1, 2 ]
What is the most elegant way to get a pandas dataframe like this: +-----+-----+-----+
| | l1 | l2 |
+-----+-----+-----+
| 0 | A | 1 |
+-----+-----+-----+
| 1 | A | 2 |
+-----+-----+--
List if i have two lists l1 = [ 'A', 'B' ]
l2 = [ 1, 2 ]
What is the most elegant way to get a pandas dataframe like this: +-----+-----+-----+
| | l1 | l2 |
+-----+-----+-----+
| 0 | A | 1 |
+-----+-----+-----+
| 1 | A | 2 |
+-----+-----+--
List if i have two lists l1 = [ 'A', 'B' ]
l2 = [ 1, 2 ]
What is the most elegant way to get a pandas dataframe like this: +-----+-----+-----+
| | l1 | l2 |
+-----+-----+-----+
| 0 | A | 1 |
+-----+-----+-----+
| 1 | A | 2 |
+-----+-----+--
username I'm pretty sure there's an easy answer to this, but due to my limited R experience I'm having a hard time solving it. I have a list of dataframes representing different experiments, and for each of these dataframes I generate a regression model - the
username I'm pretty sure there's an easy answer to this, but due to my limited R experience I'm having a hard time solving it. I have a list of dataframes representing different experiments, and for each of these dataframes I generate a regression model - the
Arnold I have a list with few elements and I want to find all possibilities to split this list into two lists. I mean, all combinations mean I don't care about the order of its elements. That is, if elements 2 and 3 are in one list, then element 1 is in the ot
Ghost Rider I have a list of lists where the variables in each inner list are paths to images. Usually each inner list is about 35 in length, and there are 9 such lists in one list. E.g [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20,
moemous Hi I have a list like this: listt = ['a','b','c','d','e','f','g','h','i','j' , 'k', 'l', 'm', 'n', 'o'] 15 members. I want to convert it to 3 lists, I used the code that works, but I want the only list. This gives me 3 lists with common members. import
moemous Hi I have a list like this: listt = ['a','b','c','d','e','f','g','h','i','j' , 'k', 'l', 'm', 'n', 'o'] 15 members. I want to convert it to 3 lists, I used the code that works, but I want the only list. This gives me 3 lists with common members. import
moemous Hi I have a list like this: listt = ['a','b','c','d','e','f','g','h','i','j' , 'k', 'l', 'm', 'n', 'o'] 15 members. I want to convert it to 3 lists, I used the code that works, but I want the only list. This gives me 3 lists with common members. import
Alex TL / DR Given X = {(A,B),(B,C),(D,E),(B,A),(C,B)}( Xone of set) How to filter the sub-tuple which shows a unique combination (rather than a unique combination) so that it Xbecomes{(A,B),(B,C),(D,E))} longer form Most combination/permutation problems here
Alex TL / DR Given X = {(A,B),(B,C),(D,E),(B,A),(C,B)}( Xone of set) How to filter the sub-tuple which shows a unique combination (rather than a unique combination) so that it Xbecomes{(A,B),(B,C),(D,E))} longer form Most combination/permutation problems here
Alex TL / DR Given X = {(A,B),(B,C),(D,E),(B,A),(C,B)}( Xone of set) How to filter the sub-tuple which shows a unique combination (rather than a unique combination) so that it Xbecomes{(A,B),(B,C),(D,E))} longer form Most combination/permutation problems here
Ravi I'm trying to get all combinations of a list where two elements that are next to each other could "be one". E.g; >>> list = ['a', 'b', 'c', 'd']
>>> get_comb(list)
[['ab', 'c' 'd'], ['a', 'bc' 'd'], ['a', 'b', 'cd'] ['ab', 'cd']]
The tricky part is that
Ravi I'm trying to get all combinations of a list where two elements that are next to each other could "be one". E.g; >>> list = ['a', 'b', 'c', 'd']
>>> get_comb(list)
[['ab', 'c' 'd'], ['a', 'bc' 'd'], ['a', 'b', 'cd'] ['ab', 'cd']]
The tricky part is that
Ravi I'm trying to get all combinations of a list where two elements that are next to each other could "be one". E.g; >>> list = ['a', 'b', 'c', 'd']
>>> get_comb(list)
[['ab', 'c' 'd'], ['a', 'bc' 'd'], ['a', 'b', 'cd'] ['ab', 'cd']]
The tricky part is that
Ravi I'm trying to get all combinations of a list where two elements that are next to each other could "be one". E.g; >>> list = ['a', 'b', 'c', 'd']
>>> get_comb(list)
[['ab', 'c' 'd'], ['a', 'bc' 'd'], ['a', 'b', 'cd'] ['ab', 'cd']]
The tricky part is that
Ravi I'm trying to get all combinations of a list where two elements that are next to each other could "be one". E.g; >>> list = ['a', 'b', 'c', 'd']
>>> get_comb(list)
[['ab', 'c' 'd'], ['a', 'bc' 'd'], ['a', 'b', 'cd'] ['ab', 'cd']]
The tricky part is that
Peaceful Kegan Liberation I'm really sorry for the title, but I don't know how to describe my problem in words. So here is the example: Assuming we have a string "123", my function should yield: 1 2 3
12 3
1 23
or for the string "1234": 1 2 3 4
12 3 4
12 34
1
Peaceful Kegan Liberation I'm really sorry for the title, but I don't know how to describe my problem in words. So here is the example: Assuming we have a string "123", my function should yield: 1 2 3
12 3
1 23
or for the string "1234": 1 2 3 4
12 3 4
12 34
1
Ben : I have a list of 15 numbers and I need to write some code to generate all 32,768 combinations of these numbers. I've found some code (by googling) that apparently does what I want, but I've found the code to be rather opaque and have been cautious about
Minatverma Given an array say x = ['A','I','R']I want the output as [['A','I','R'],['A','I'],['I','R'],['A'],['I'],['R']]
What I don't want as output is: [['A','I','R'],['A','I'],['I','R'],['A','R'],['A'],['I'],['R']] # extra ['A','R'] which is not in sequen
Ben : I have a list of 15 numbers and I need to write some code to generate all 32,768 combinations of these numbers. I've found some code (by googling) that apparently does what I want, but I've found the code to be rather opaque and have been cautious about
Minatverma Given an array say x = ['A','I','R']I want the output as [['A','I','R'],['A','I'],['I','R'],['A'],['I'],['R']]
What I don't want as output is: [['A','I','R'],['A','I'],['I','R'],['A','R'],['A'],['I'],['R']] # extra ['A','R'] which is not in sequen
Milano Is it possible to get all element combinations if they are neighbors? Here is an example: Edit: I want to use this on strings, not just numbers. E.g:[Explain,it,to,me,please] List: [0,1,2,3,4]
result: [0,1,2,3,4],
[0,1,2,3],
[1,2,3,4],
[0,1,2],
[1,2,3]
Ben : I have a list of 15 numbers and I need to write some code to generate all 32,768 combinations of these numbers. I've found some code (by googling) that apparently does what I want, but I've found the code to be rather opaque and have been cautious about
Minatverma Given an array say x = ['A','I','R']I want the output as [['A','I','R'],['A','I'],['I','R'],['A'],['I'],['R']]
What I don't want as output is: [['A','I','R'],['A','I'],['I','R'],['A','R'],['A'],['I'],['R']] # extra ['A','R'] which is not in sequen