Related
user3207586 I want to receive the url parameters in the method View::composer but I don't know how to do it... This is in filters.php: View::composer('profile.followers', function($view){
dd($view->parameters);
$view->with('menus', $menus);
});
This i
username I want to receive url parameter in method View::composerbut I don't know how to do it... This is in filters.php: View::composer('profile.followers', function($view){
dd($view->parameters);
$view->with('menus', $menus);
});
Here is my route: R
username I want to receive url parameter in method View::composerbut I don't know how to do it... This is in filters.php: View::composer('profile.followers', function($view){
dd($view->parameters);
$view->with('menus', $menus);
});
Here is my route: R
Javier Munoz I have the following HTML with jQuery code: <div id="info" style="width: 100%; height: 280px; overflow-y: scroll;"></div>
var url1 = cbcWMS1.getGetFeatureInfoUrl
(evt.coordinate, viewResolution, 'EPSG:3857', {'INFO_FORMAT': 'text/html'});
$('#in
Beulah Akindele I have a functional component trying to access a URL parameter already named in react-router via a hook. useEffect(() => {
document.title = props.match.params.subject
UserServices.getSubject(props.match.params.subject)
.then(resp
Beulah Akindele I have a functional component trying to access a URL parameter already named in react-router via a hook. useEffect(() => {
document.title = props.match.params.subject
UserServices.getSubject(props.match.params.subject)
.then(resp
Javier Munoz I have the following HTML with jQuery code: <div id="info" style="width: 100%; height: 280px; overflow-y: scroll;"></div>
var url1 = cbcWMS1.getGetFeatureInfoUrl
(evt.coordinate, viewResolution, 'EPSG:3857', {'INFO_FORMAT': 'text/html'});
$('#in
Beulah Akindele I have a functional component trying to access a URL parameter already named in react-router via a hook. useEffect(() => {
document.title = props.match.params.subject
UserServices.getSubject(props.match.params.subject)
.then(resp
Beulah Akindele I have a functional component trying to access a URL parameter already named in react-router via a hook. useEffect(() => {
document.title = props.match.params.subject
UserServices.getSubject(props.match.params.subject)
.then(resp
Beulah Akindele I have a functional component trying to access a URL parameter already named in react-router via a hook. useEffect(() => {
document.title = props.match.params.subject
UserServices.getSubject(props.match.params.subject)
.then(resp
Roberto Bonvallet I'm writing a very simple Angular application that displays information about football tournaments. For each tournament in the database, I want to display a view of the match or stats, so I'm implementing the following simple URL scheme: foo/
kale I'm trying to write custom rest_framework permissions to prevent users from querying information that is not in the same company as them. Unfortunately, I can't seem to access any URL parameters from has_permission()or has_object_permissions(). Here is th
Anuj TBE In the cookbook for cakephp 3. Given the following command to build the URL echo $this->Url->build([
"controller" => "Posts",
"action" => "view",
"foo" => "bar"
]);
will output as /posts/view/foo:bar
How to access foo:barin action and sa
kale I'm trying to write custom rest_framework permissions to prevent users from querying information that is not in the same company as them. Unfortunately, I can't seem to access any URL parameters from has_permission()or has_object_permissions(). Here is th
Noamyoungerm For some pages in my application, I want to enable printable mode, where some elements of the page are hidden when URL parameters are included ?print=true. For now, I've tried a workaround that involves sending the URL parameters as a data context
kale I'm trying to write custom rest_framework permissions to prevent users from querying information that is not in the same company as them. Unfortunately, I can't seem to access any URL parameters from has_permission()or has_object_permissions(). Here is th
Karsten I want to access Java enums in thymeleaf. I think it will work like this <a th:href="@{/(somekey=T(com.example.Myenum.FOO.getBaz()))}">my link</a>
Unfortunately, that's not the case. I searched a lot of examples but couldn't find a solution, do you ha
Noamyoungerm For some pages in my application, I want to enable printable mode, where some elements of the page are hidden when URL parameters are included ?print=true. For now, I've tried a workaround that involves sending the URL parameters as a data context
Karsten I want to access Java enums in thymeleaf. I think it will work like this <a th:href="@{/(somekey=T(com.example.Myenum.FOO.getBaz()))}">my link</a>
Unfortunately, that's not the case. I searched a lot of examples but couldn't find a solution, do you ha
Solab How to access URL in Django view. I have view handling for the following 5 urls: localhost:8000/standings/
localhost:8000/standings/q1
localhost:8000/standings/q2
localhost:8000/standings/q3
localhost:8000/standings/q4
my opinion is class StandingsView(
Solab How to access URL in Django view. I have view handling for the following 5 urls: localhost:8000/standings/
localhost:8000/standings/q1
localhost:8000/standings/q2
localhost:8000/standings/q3
localhost:8000/standings/q4
my opinion is class StandingsView(
Solab How to access URL in Django view. I have view handling for the following 5 urls: localhost:8000/standings/
localhost:8000/standings/q1
localhost:8000/standings/q2
localhost:8000/standings/q3
localhost:8000/standings/q4
my opinion is class StandingsView(
Solab How to access URL in Django view. I have view handling for the following 5 urls: localhost:8000/standings/
localhost:8000/standings/q1
localhost:8000/standings/q2
localhost:8000/standings/q3
localhost:8000/standings/q4
my opinion is class StandingsView(
Alex I have a companymodel and each instance of it has a foreign key named for the adminuser . I'm writing a view to allow company admins to manage their company: urls.py: path('admin/crn=<company_spec_url>', CompanyAdminView.as_view(), name="CompanyAdminView"
username I want to get the URL parameter from the URL of the current page in XSL and use it to test the condition in the template xpath. E.g: <xsl:apply-templates select="//search-results/orders/order[@id = URL Parameter]" mode="tableContent"/>
I have no con
George Patterson I am very new to Rails and ruby code. I have passed many parameters to the URL from link_to. However, when I try to access the parameter in _form.html.erb, I don't get any errors, but it doesn't output the parameter. Any help would be greatly
George Patterson I am very new to Rails and ruby code. I have passed many parameters to the URL from link_to. However, when I try to access the parameter in _form.html.erb, I don't get any errors, but it doesn't output the parameter. Any help would be greatly
George Patterson I am very new to Rails and ruby code. I have passed many parameters to the URL from link_to. However, when I try to access the parameter in _form.html.erb, I don't get any errors, but it doesn't output the parameter. Any help would be greatly
username I want to get the URL parameter from the URL of the current page in XSL and use it to test the condition in the template xpath. E.g: <xsl:apply-templates select="//search-results/orders/order[@id = URL Parameter]" mode="tableContent"/>
I have no con