Pass arguments with spaces to command from shell script?

Adi Gerber

See edit below, thanks

I have the following test script ( IMPORTANT: I ​​cannot change this part ):

while (($#)); do
  echo $1
  shift
done

Running the command ./test aaa "bbbb cccc" dddwill give the following output:

aaa
bbbb cccc
ddd

This is what any sane person would expect.

I have another script:

mode="good"
status="okay"
name="bro"
description="very good man dood"
extra=""

# ----

PARAMS=""

// $1: key, $2: value
function addParam {
    if [ ! -z "$2" ]; then
        PARAMS="$PARAMS --$1 \"$2\""
    fi
}

addParam "mode" "$mode"
addParam "status" "$status"
addParam "name" "$name"
addParam "description" "$description"
addParam "extra" "$extra"

echo ./test $PARAMS
./test $PARAMS

from the output echo, ./test --mode "good" --status "okay" --name "bro" --description "very good man dood"so my expected output ./test $PARAMSis

--mode
good
--status
okay
--name
bro
--description
very good man dood

But for some reason I get the following output:

--mode
"good"
--status
"okay"
--name
"bro"
--description
"very
good
man
dood"

If I copy echo ./test $PARAMSand paste its output , I get the expected output from it ./test. So I've tried removing the last line of execution and ./testleaving the last line on the last line, but that still doesn't work, echoapparently , and more than I thought.$(./script)

What am I doing wrong?

EDIT: @steeldriver's solution works, but has another drawback - I have to allow users to send their own parameters.

So having this script (thanks @steeldriver):

#!/bin/bash

mode="good"
status="okay"
name="bro"
description="very good man dood"
extra=""
arguments="--config \"blablabla=yes\" --config2 \"bla2=no problem\""

# ----

declare -a PARAMS

# $1: key, $2: value
function addParam {
    if [ ! -z "$2" ]; then
        PARAMS+=("--$1" "$2")
    fi
}

addParam "mode" "$mode"
addParam "status" "$status"
addParam "name" "$name"
addParam "description" "$description"
addParam "extra" "$extra"

# (1)
PARAMS+=("$arguments")

# (2)
PARAMS+=($arguments)

echo ./test "${PARAMS[@]}" 
./test "${PARAMS[@]}"

The desired output is:

--mode
good
--status
okay
--name
bro
--description
very good man dood
--config
blablabla=yes
--config2
bla2=no problem

But the output I get is:

with (1):

--mode
good
--status
okay
--name
bro
--description
very good man dood
--config "blablabla=yes" --config2 "bla2=no problem"

with (2):

--mode
good
--status
okay
--name
bro
--description
very good man dood
--config
"blablabla=yes"
--config2
"bla2=no
problem"

Very grateful!

Adi Gerber

Thanks to @steeldriver's attention, I managed to add the user parameter correctly and get the desired output. Now my script:

#!/bin/bash

mode="good"
status="okay"
name="bro"
description="very good man dood"
extra=""
arguments="--config \"blablabla=yes\" --config2 \"bla2=no problem\""

# ----

declare -a PARAMS

# $1: key, $2: value
function addParam {
    if [ ! -z "$2" ]; then
        PARAMS+=("--$1" "$2")
    fi
}

# This function right here
function addUserArguments {
    while (($#)); do
      PARAMS+=("$1")
      shift
    done
}

addParam "mode" "$mode"
addParam "status" "$status"
addParam "name" "$name"
addParam "description" "$description"
addParam "extra" "$extra"

# And this line right here
eval addUserArguments $arguments

./test "${PARAMS[@]}"

the output is

--mode
good
--status
okay
--name
bro
--description
very good man dood
--config
blablabla=yes
--config2
bla2=no problem

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