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Tfb9 I am new to Linux environment. After a quick search, I couldn't find a useful question about the $ operator used in bash scripts. I don't know if this question is related to the Ubuntu (or other) flavor of Linux, or my programming experience. Basically, I
Tony I have a bash script that helps and then use awk to get some variables - the first works fine, but the second has a leading $ and trailing \r... any ideas? #!/bin/bash
newTS=$( cat times.txt | awk -F';' '{print $2}')
ctime=$( cat times.txt | awk -F';' '{p
Noppadet i get error Operand type is incompatible with operator Click OK in the header when trying to compare two "real" data types. Can anyone help me with what problem? public void clicked()
{
real localAnnualUsage = itemSetup_DS.AnnualUsage();
Noppadet i get error Operand type is incompatible with operator Click OK in the header when trying to compare two "real" data types. Can anyone help me with what problem? public void clicked()
{
real localAnnualUsage = itemSetup_DS.AnnualUsage();
Diogo Martinho I'm currently trying to define a dynamic query in Linq and I'm getting the following error: My query is as follows: valuesList = valuesList.Where("(position=1 OR value LIKE '%3%')")
What am I doing wrong? Ishida try this - you can't pass string
newer I have a method which generally forms my qeury. It looks like this: private static string PrepareWhereClause(string[] columns)
{
var query = $"({string.Join(" OR ", columns?.Select(c => $"{c} != null AND {c}.ToLower().Contains(@0)"))}
Latheesan I'm working on a bash script that needs to create files at: /etc/yum.repos.d/nginx.repo has the following: [nginx]
name=nginx repo
baseurl=http://nginx.org/packages/centos/$releasever/$basearch/
gpgcheck=0
enabled=1
So I try to do this: cat >/etc/yu
Latheesan I'm working on a bash script that needs to create files at: /etc/yum.repos.d/nginx.repo has the following: [nginx]
name=nginx repo
baseurl=http://nginx.org/packages/centos/$releasever/$basearch/
gpgcheck=0
enabled=1
So I try to do this: cat >/etc/yu
Latheesan I'm working on a bash script that needs to create files at: /etc/yum.repos.d/nginx.repo has the following: [nginx]
name=nginx repo
baseurl=http://nginx.org/packages/centos/$releasever/$basearch/
gpgcheck=0
enabled=1
So I try to do this: cat >/etc/yu
Amir Afghani I'm running this little test script I wrote: #!/bin/bash
TESTCASE=$@
testHarness <<runTest
$TESTCASE
runTest
From the command line: ./test.sh "1092$212"
But the dollar sign is stripped. If I get away with it, that's fine. But I think double quo
Amir Afghani I'm running this little test script I wrote: #!/bin/bash
TESTCASE=$@
testHarness <<runTest
$TESTCASE
runTest
From the command line: ./test.sh "1092$212"
But the dollar sign is stripped. If I get away with it, that's fine. But I think double quo
Andrey Chernukha this code: bool contains = std::find(indexes.begin(), indexes.end(), i) != indexes.end();
CardAbility* cardAbility = contains ? new CardAbilityBurn(i) : new CardAbilityEmpty;
gives me the following error: Incompatible operand types CardAb
Andrey Chernukha this code: bool contains = std::find(indexes.begin(), indexes.end(), i) != indexes.end();
CardAbility* cardAbility = contains ? new CardAbilityBurn(i) : new CardAbilityEmpty;
gives me the following error: Incompatible operand types CardAb
Andrey Chernukha this code: bool contains = std::find(indexes.begin(), indexes.end(), i) != indexes.end();
CardAbility* cardAbility = contains ? new CardAbilityBurn(i) : new CardAbilityEmpty;
gives me the following error: Incompatible operand types CardAb
Andrey Chernukha this code: bool contains = std::find(indexes.begin(), indexes.end(), i) != indexes.end();
CardAbility* cardAbility = contains ? new CardAbilityBurn(i) : new CardAbilityEmpty;
gives me the following error: Incompatible operand types CardAb
Andrey Chernukha this code: bool contains = std::find(indexes.begin(), indexes.end(), i) != indexes.end();
CardAbility* cardAbility = contains ? new CardAbilityBurn(i) : new CardAbilityEmpty;
gives me the following error: Incompatible operand types CardAb
Eli Sadoff Haskell's dollar sign is a great function, f $ ge.g. for , evaluates fwith the result gof . This works fine sin $ sqrt $ abs $ f 2
equivalent to sin(sqrt(abs(f(2))))
The dollar sign works fine for me because it's more readable. I've noticed |>what
Eli Sadoff Haskell's dollar sign is a great function, f $ ge.g. for , evaluates fwith the result gof . This works fine sin $ sqrt $ abs $ f 2
equivalent to sin(sqrt(abs(f(2))))
The dollar sign works fine for me because it's more readable. I've noticed |>what
Eli Sadoff Haskell's dollar sign is a great function, f $ ge.g. for , evaluates fwith the result gof . This works fine sin $ sqrt $ abs $ f 2
equivalent to sin(sqrt(abs(f(2))))
The dollar sign works fine for me because it's more readable. I've noticed |>what
Eli Sadoff Haskell's dollar sign is a great function, f $ ge.g. for , evaluates fwith the result gof . This works fine sin $ sqrt $ abs $ f 2
equivalent to sin(sqrt(abs(f(2))))
The dollar sign works fine for me because it's more readable. I've noticed |>what
Eli Sadoff Haskell's dollar sign is a great function, f $ ge.g. for , evaluates fwith the result gof . This works fine sin $ sqrt $ abs $ f 2
equivalent to sin(sqrt(abs(f(2))))
The dollar sign works fine for me because it's more readable. I've noticed |>what
Eli Sadoff Haskell's dollar sign is a great function, f $ ge.g. for , evaluates fwith the result gof . This works fine sin $ sqrt $ abs $ f 2
equivalent to sin(sqrt(abs(f(2))))
The dollar sign works fine for me because it's more readable. I've noticed |>what
0x90： inawk : 1 tolower($1) ~ /mary/ { print "CI Record: " $0; }
2 $0 !~ /Mary/ { print "Not Mary: " $0; }
3 $1 == "Mary" { print "Mary Record: " $0; }
Why 1and 3compare $1and 2use $0? Anubava: In fact, the example is using regular expressions # 2becaus
Sibbs Gambling Our school uses SLURM as a queuing system where some "prologue" must be specified before other commands are executed. So in this case the shell script usually starts with #!/bin/bash
#SBATCH -n 10 # Number of cores requested
#SBAT
0x90： inawk : 1 tolower($1) ~ /mary/ { print "CI Record: " $0; }
2 $0 !~ /Mary/ { print "Not Mary: " $0; }
3 $1 == "Mary" { print "Mary Record: " $0; }
Why 1and 3compare $1and 2use $0? Anubava: In fact, the example is using regular expressions # 2becaus
Sibbs Gambling Our school uses SLURM as a queuing system where some "prologue" must be specified before other commands are executed. So in this case the shell script usually starts with #!/bin/bash
#SBATCH -n 10 # Number of cores requested
#SBAT
Ed Branning I just saw this in an init script: echo $"Stopping Apache"
What is this dollar sign for? My research so far: I found this in the bash manual: quotation marks If set $'string'and $"string"enclosed within quotes, ${parameter}double-quoted expansion
John Totugo: When inserting a shell script in a Makefile, we can use (?) double dollar signs ($$) to refer to variables. why? for number in 1 2 3 4 ; do \
echo $$number ; \
done
Anubava: According to the official documentation of gnu make : Variable and f
McSaman I'm trying to avoid getting hit hard, but trying to get some core fundamentals. I can see that arithmetic statements are defined by double brackets ((5-3))
But if I try echoto do this or we try , I shiftget an error echo ((5-3))
-bash: syntax error ne