How to get all possible combinations of elements of an (integer) array?

loone96 ：

I've been writing code to get all combinations of elements from an array, but I don't know how to do it. Can you guys give me some advice?

This is what I want to do...

            int[] num = {1, 2, 3, 4, 5};
            int n = num.length;
            int length = (n * (n - 1)) / 2;
            int[] list = new int[length];

            for (int j = 0; j < n - 1; j++) {
                for (int p = 4;p < n; p--) {
                    for (int i = 0; (I < length); i++) {
                        list[i] = Math.abs(num[j] - num[j + p]);
                    }
                    p++;        
                }
            }

My list of results looks like this.

list = {1, 2, 3, 4, 1, 2, 3, 1, 2, 1};

Thank you in advance.

EDIT: I'm so sorry I didn't post my question clearly. What I want to do is get the absolute value of each value subtracted from the array. For example 1-2, 1-3, 1-4, 1-5, 2-3, 2-4, 2-5, 3-4, 3-5, 4.5

for (int v : list) {
    System.out.println(v);
}

Output: 1 2 3 4 1 2 ...

Arvind Kumar Avinash：

Proceed as follows:

import java.util.Arrays;

public class Main {
    public static void main(String[] args) {
        int[] num = { 1, 2, 3, 4, 5 };
        int n = num.length;
        int length = (n * (n - 1)) / 2;
        int[] list = new int[length];

        // Index counter for list[]
        int c = 0;

        for (int i = n - 1; i >= 0; i--) {
            for (int j = 0; j < i; j++) {
                list[c++] = num[j];
            }
        }

        // Display
        System.out.println(Arrays.toString(list));
    }
}

output:

[1, 2, 3, 4, 1, 2, 3, 1, 2, 1]

How to get all possible combinations of elements of an (integer) array?

loone96 ： I've been writing code to get all combinations of elements from an array, but I don't know how to do it. Can you guys give me some advice? This is what I want to do... int[] num = {1, 2, 3, 4, 5}; int n = num.length;

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