Running a shell command in Scala code on Windows seems to require the full absolute path to the command

Cui Pengfei

When I try to run the shell command on the Mac it works as expected like this:

scala> import scala.sys.process._
import scala.sys.process._

scala> """protractor --version"""!
warning: there were 1 feature warning(s); re-run with -feature for details
Version 0.24.0
res12: Int = 0

scala>

However, if I do this on Windows, I get this:

scala> import scala.sys.process._
import scala.sys.process._

scala> """protractor --version"""!
warning: there were 1 feature warning(s); re-run with -feature for details
java.io.IOException: Cannot run program "protractor": CreateProcess error=2, The system cannot find the file specified
        at java.lang.ProcessBuilder.start(ProcessBuilder.java:1041)

It seems I have to do this on Windows:

scala> import scala.sys.process._
scala> """C:\Users\twer\AppData\Roaming\npm\protractor.cmd --version"""!
warning: there were 1 feature warning(s); re-run with -feature for details
Version 0.24.0
res11: Int = 0

scala>

I have to provide the full absolute path to the command.

But I'm sure the command is available in the path.

Is there anyway to avoid this?

Daniel Nixon

You can try the following:

val command = Seq("protractor", "--version")
val os = sys.props("os.name").toLowerCase
val panderToWindows = os match {
  case x if x contains "windows" => Seq("cmd", "/C") ++ command
  case _ => command
}
panderToWindows.!

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