Related
Kronal kp: This doesn't print anything: from itertools import combinations
comb = combinations([1,2], 3)
for i in comb:
print(i)
I want the output to be: (1,2,2) (1,2,1) (1,1,2) (1,1,1) (2,1,2) (2,1,1) (2,2,1) (2,2,2)
ShadowRanger： It seems that you only
Kronal kp: This doesn't print anything: from itertools import combinations
comb = combinations([1,2], 3)
for i in comb:
print(i)
I want the output to be: (1,2,2) (1,2,1) (1,1,2) (1,1,1) (2,1,2) (2,1,1) (2,2,1) (2,2,2)
ShadowRanger： It seems that you only
Kronal kp: This doesn't print anything: from itertools import combinations
comb = combinations([1,2], 3)
for i in comb:
print(i)
I want the output to be: (1,2,2) (1,2,1) (1,1,2) (1,1,1) (2,1,2) (2,1,1) (2,2,1) (2,2,2)
ShadowRanger： It seems that you only
Kronal kp: This doesn't print anything: from itertools import combinations
comb = combinations([1,2], 3)
for i in comb:
print(i)
I want the output to be: (1,2,2) (1,2,1) (1,1,2) (1,1,1) (2,1,2) (2,1,1) (2,2,1) (2,2,2)
ShadowRanger： It seems that you only
Tobias Herman I need a function that does the same thing as itertools.combinations(iterable, r) in python So far I came up with this: {-| forward application -}
x -: f = f x
infixl 0 -:
{-| combinations 2 "ABCD" = ["AB","AC","AD","BC","BD","CD"] -}
combinatio
Tobias Herman I need a function that does the same thing as in pythonitertools.combinations(iterable, r) So far I have come up with this: {-| forward application -}
x -: f = f x
infixl 0 -:
{-| combinations 2 "ABCD" = ["AB","AC","AD","BC","BD","CD"] -}
combin
Suri Chitti In a way this is the opposite of the problem of generating a subset of size k from an array with k+1 elements. For example, if someone gives me {a,b},{a,c},{b,c},{a,e},{b,e},{a,f} pairs, then I need an algorithm that will tells me that the triples
Suri Chitti In a way this is the opposite of the problem of generating a subset of size k from an array with k+1 elements. For example, if someone gives me {a,b},{a,c},{b,c},{a,e},{b,e},{a,f} pairs, then I need an algorithm that will tells me that the triples
loris itertools.combinations(iterable,k)For large test cases, I use a rather time-consuming approach . Is there any way to make it faster. For example, I have a list of numbers:[1,2,3] List of all possible "2" combinations:[(1,2),(1,3),(2,3)] Any help is appre
Minatverma Given an array say x = ['A','I','R']I want the output as [['A','I','R'],['A','I'],['I','R'],['A'],['I'],['R']]
What I don't want as output is: [['A','I','R'],['A','I'],['I','R'],['A','R'],['A'],['I'],['R']] # extra ['A','R'] which is not in sequen
Minatverma Given an array say x = ['A','I','R']I want the output as [['A','I','R'],['A','I'],['I','R'],['A'],['I'],['R']]
What I don't want as output is: [['A','I','R'],['A','I'],['I','R'],['A','R'],['A'],['I'],['R']] # extra ['A','R'] which is not in sequen
Minatverma Given an array say x = ['A','I','R']I want the output as [['A','I','R'],['A','I'],['I','R'],['A'],['I'],['R']]
What I don't want as output is: [['A','I','R'],['A','I'],['I','R'],['A','R'],['A'],['I'],['R']] # extra ['A','R'] which is not in sequen
Minatverma Given an array say x = ['A','I','R']I want the output as [['A','I','R'],['A','I'],['I','R'],['A'],['I'],['R']]
What I don't want as output is: [['A','I','R'],['A','I'],['I','R'],['A','R'],['A'],['I'],['R']] # extra ['A','R'] which is not in sequen
Ben : I have a list of 15 numbers and I need to write some code to generate all 32,768 combinations of these numbers. I've found some code (by googling) that apparently does what I want, but I've found the code to be rather opaque and have been cautious about
Ben : I have a list of 15 numbers and I need to write some code to generate all 32,768 combinations of these numbers. I've found some code (by googling) that apparently does what I want, but I've found the code to be rather opaque and have been cautious about
Ben : I have a list of 15 numbers and I need to write some code to generate all 32,768 combinations of these numbers. I've found some code (by googling) that apparently does what I want, but I've found the code to be rather opaque and have been cautious about
Camille I'm trying to write a function that iterateshould generate all combinations of elements: f :: [a] -> [[[a]]]
f [1,2] =
[ [[1] , [2]] -- all combinations of length 1
, [[1,1],[1,2],[2,1],[2,2]], -- all combinations of length 2
Camille I'm trying to write a function that iterateshould generate all combinations of elements: f :: [a] -> [[[a]]]
f [1,2] =
[ [[1] , [2]] -- all combinations of length 1
, [[1,1],[1,2],[2,1],[2,2]], -- all combinations of length 2
Camille I'm trying to write a function that iterateshould generate all combinations of elements: f :: [a] -> [[[a]]]
f [1,2] =
[ [[1] , [2]] -- all combinations of length 1
, [[1,1],[1,2],[2,1],[2,2]], -- all combinations of length 2
Camille I'm trying to write a function that iterateshould generate all combinations of elements: f :: [a] -> [[[a]]]
f [1,2] =
[ [[1] , [2]] -- all combinations of length 1
, [[1,1],[1,2],[2,1],[2,2]], -- all combinations of length 2
Camille I'm trying to write a function that iterateshould generate all combinations of elements: f :: [a] -> [[[a]]]
f [1,2] =
[ [[1] , [2]] -- all combinations of length 1
, [[1,1],[1,2],[2,1],[2,2]], -- all combinations of length 2
math ripper I have a list [x,y,z] where x,y,z can take any value in {0,1}. I want to find all possible combinations like [0,0,0],[1,0,0], [1,1,0],... in Python. I've seen similar questions asked before, but they're slightly different from what I'm trying to ac
Scion 4581 Can someone help me? I am trying to find the formula and write a piece of code in PHP language which makes the next step Imagine we have 3 types of things, k = 1, 2, 3, and the length of this number can be different (n length), but adjacent types sh
CMinusMinus： I want to get all combinations of lists: L = ["a","b","c"]
combinations(L,length=2)
# [("a","a"),("a","b"),("a","c"),("b","a"),("b","b"),("b","c"),("c","a"),("c","b"),("c","c")]
I tried itertools.combinations() but it's back [('a', 'b'), ('a', 'c
CMinusMinus： I want to get all combinations of lists: L = ["a","b","c"]
combinations(L,length=2)
# [("a","a"),("a","b"),("a","c"),("b","a"),("b","b"),("b","c"),("c","a"),("c","b"),("c","c")]
I tried itertools.combinations() but it's back [('a', 'b'), ('a', 'c
CMinusMinus： I want to get all combinations of lists: L = ["a","b","c"]
combinations(L,length=2)
# [("a","a"),("a","b"),("a","c"),("b","a"),("b","b"),("b","c"),("c","a"),("c","b"),("c","c")]
I tried itertools.combinations() but it's back [('a', 'b'), ('a', 'c
TheRealTengri： I am trying to get all combinations of a list. Here is an example: >>> l = [1, 2, 3]
>>> combo = something
>>> print(combo)
[1, 2, 3, 12, 13, 21, 23, 31, 32, 123, 132, 213, 231, 312, 321]
Here's what I've tried so far: >>> import itertools
>>>
TheRealTengri： I am trying to get all combinations of a list. Here is an example: >>> l = [1, 2, 3]
>>> combo = something
>>> print(combo)
[1, 2, 3, 12, 13, 21, 23, 31, 32, 123, 132, 213, 231, 312, 321]
Here's what I've tried so far: >>> import itertools
>>>
TheRealTengri： I am trying to get all combinations of a list. Here is an example: >>> l = [1, 2, 3]
>>> combo = something
>>> print(combo)
[1, 2, 3, 12, 13, 21, 23, 31, 32, 123, 132, 213, 231, 312, 321]
Here's what I've tried so far: >>> import itertools
>>>