Related
Grotaire I overloaded both the operator ==and the !=operator and would like the latter to reference the former so that no code is repeated at all. Here is what I wrote: bool Date :: operator == (const Date & other) const {
bool are_equal = Year() == other.
Cola I got this error when using Qt 5.12 on Ubuntu Focal. However, when I use Qt 5.13.2 and above, no errors are shown. I want it to work in 5.12 and below, how to do it? TQProfile::TQProfile()
{
type = "abc";
abcSettings = ConfigHelper::generateAbcSet
Cola I got this error when using Qt 5.12 on Ubuntu Focal. However, when I use Qt 5.13.2 and above, no errors are shown. I want it to work in 5.12 and below, how to do it? TQProfile::TQProfile()
{
type = "abc";
abcSettings = ConfigHelper::generateAbcSet
Grotaire I overloaded both the operator ==and the !=operator and would like the latter to reference the former so that no code is repeated at all. Here is what I wrote: bool Date :: operator == (const Date & other) const {
bool are_equal = Year() == other.
Cola I got this error when using Qt 5.12 on Ubuntu Focal. However, when I use Qt 5.13.2 and above, no errors are shown. I want it to work in 5.12 and below, how to do it? TQProfile::TQProfile()
{
type = "abc";
abcSettings = ConfigHelper::generateAbcSet
Grotaire I overloaded both the operator ==and the !=operator and would like the latter to reference the former so that no code is repeated at all. Here is what I wrote: bool Date :: operator == (const Date & other) const {
bool are_equal = Year() == other.
Cola I got this error when using Qt 5.12 on Ubuntu Focal. However, when I use Qt 5.13.2 and above, no errors are shown. I want it to work in 5.12 and below, how to do it? TQProfile::TQProfile()
{
type = "abc";
abcSettings = ConfigHelper::generateAbcSet
Cola I got this error when using Qt 5.12 on Ubuntu Focal. However, when I use Qt 5.13.2 and above, no errors are shown. I want it to work in 5.12 and below, how to do it? TQProfile::TQProfile()
{
type = "abc";
abcSettings = ConfigHelper::generateAbcSet
Grotaire I overloaded both the operator ==and the !=operator and would like the latter to reference the former so that no code is repeated at all. Here is what I wrote: bool Date :: operator == (const Date & other) const {
bool are_equal = Year() == other.
Grotaire I overloaded both the operator ==and the !=operator and would like the latter to reference the former so that no code is repeated at all. Here is what I wrote: bool Date :: operator == (const Date & other) const {
bool are_equal = Year() == other.
Cola I got this error when using Qt 5.12 on Ubuntu Focal. However, when I use Qt 5.13.2 and above, no errors are shown. I want it to work in 5.12 and below, how to do it? TQProfile::TQProfile()
{
type = "abc";
abcSettings = ConfigHelper::generateAbcSet
Cola I got this error when using Qt 5.12 on Ubuntu Focal. However, when I use Qt 5.13.2 and above, no errors are shown. I want it to work in 5.12 and below, how to do it? TQProfile::TQProfile()
{
type = "abc";
abcSettings = ConfigHelper::generateAbcSet
core I have some errors in my code and I don't know how to fix it. The error is: error: mismatch of 'operator ==' (operand types are 'const Secuencia' and const Secuencia')
if (sec1 == sec2)
Note: Candidate: "bool Secuencia::operator==(const Secuencia&)"
bool
cdn I have one std::unique_ptr<std::vector<int>>and I am trying to access an element using []an operator . How can I access a specific index of a vector contained in std::unique_ptr?? #include <memory>
#include <vector>
int main()
{
std::unique_ptr<std::v
core I have some errors in my code and I don't know how to fix it. The error is: error: mismatch of 'operator ==' (operand types are 'const Secuencia' and const Secuencia')
if (sec1 == sec2)
Note: Candidate: "bool Secuencia::operator==(const Secuencia&)"
bool
core I have some errors in my code and I don't know how to fix it. The error is: error: mismatch of 'operator ==' (operand types are 'const Secuencia' and const Secuencia')
if (sec1 == sec2)
Note: Candidate: "bool Secuencia::operator==(const Secuencia&)"
bool
Zehryo Karham OS: Windows 7 64bit IDE: Qt Creator 5.7.0 (32 bit) Compiler: MinGW 5.3.0 (32 bit) As a preface, this is an exercise to help me understand the mechanics of some pointers/classes, so bool no = 1;I don't want to use <vector>s or any other easyToUset
core I have some errors in my code and I don't know how to fix it. The error is: error: mismatch of 'operator ==' (operand types are 'const Secuencia' and const Secuencia')
if (sec1 == sec2)
Note: Candidate: "bool Secuencia::operator==(const Secuencia&)"
bool
Hugo Sohm Actually, I'm trying to use the visitor pattern with some templates. I want to parse unordered_mapthe includes type_indexand functionvariables, but even after reading a lot on the subject, I still can't understand the compile error. error: no match f
Hugo Sohm Actually, I'm trying to use the visitor pattern with some templates. I want to parse unordered_mapthe includes type_indexand functionvariables, but even after reading a lot on the subject, I still can't understand the compile error. error: no match f
Hugo Sohm Actually, I'm trying to use the visitor pattern with some templates. I want to parse unordered_mapthe includes type_indexand functionvariables, but even after reading a lot on the subject, I still can't understand the compile error. error: no match f
Hugo Sohm Actually, I'm trying to use the visitor pattern with some templates. I want to parse unordered_mapthe includes type_indexand functionvariables, but even after reading a lot on the subject, I still can't understand the compile error. error: no match f
Hugo Sohm Actually, I'm trying to use the visitor pattern with some templates. I want to parse unordered_mapthe includes type_indexand functionvariables, but even after reading a lot on the subject, I still can't understand the compile error. error: no match f
username Which type of operator uses the logical AND operator (&)? I need to input AND shorts aand a "number" mfrom 1 to 16 and get another short b. That primitive type must be m? example: ? m = ...; //with 1 <= m <= 16
short a = 2;
short b = a & m;
The examp
username Which type of operator uses the logical AND operator (&)? I need to input AND shorts aand a "number" mfrom 1 to 16 and get another short b. That primitive type must be m? example: ? m = ...; //with 1 <= m <= 16
short a = 2;
short b = a & m;
The examp
Diogo Martinho I'm currently trying to define a dynamic query in Linq and I'm getting the following error: My query is as follows: valuesList = valuesList.Where("(position=1 OR value LIKE '%3%')")
What am I doing wrong? Ishida try this - you can't pass string
newer I have a method which generally forms my qeury. It looks like this: private static string PrepareWhereClause(string[] columns)
{
var query = $"({string.Join(" OR ", columns?.Select(c => $"{c} != null AND {c}.ToLower().Contains(@0)"))}
Oops I wrapped the variant's get function with a template function that returns the type defined in the struct of the aliased type. I should be able to enter an alias type in the template and have the function return a value of that type, however, the type fai
Oops I wrapped the variant's get function with a template function that returns the type defined in the struct of the aliased type. I should be able to enter an alias type in the template and have the function return a value of that type, however, the type fai