Related
username I'm watching one of Jeffs Laracast's tutorials on coding rules. function signUp($subscription)
{
if ($subscription == 'monthly')
{
$this->createMonthlySubscription();
}
elseif ($subscription == 'forever')
{
$this->
username I'm watching one of Jeffs Laracast's tutorials on coding rules. function signUp($subscription)
{
if ($subscription == 'monthly')
{
$this->createMonthlySubscription();
}
elseif ($subscription == 'forever')
{
$this->
username I'm watching one of Jeffs Laracast's tutorials on coding rules. function signUp($subscription)
{
if ($subscription == 'monthly')
{
$this->createMonthlySubscription();
}
elseif ($subscription == 'forever')
{
$this->
username I'm watching one of Jeffs Laracast's tutorials on coding rules. function signUp($subscription)
{
if ($subscription == 'monthly')
{
$this->createMonthlySubscription();
}
elseif ($subscription == 'forever')
{
$this->
User 7780894 I've seen someone do this: usort($array, function() {
//...
});
How can I write a similar implementation with my own functions? E.g: runIt(function() {
//...
});
and implementation runIt: function runIt() {
// do something with pass
User 7780894 I've seen someone do this: usort($array, function() {
//...
});
How can I write a similar implementation with my own functions? E.g: runIt(function() {
//...
});
and implementation runIt: function runIt() {
// do something with pass
User 7780894 I've seen someone do this: usort($array, function() {
//...
});
How can I write a similar implementation with my own functions? E.g: runIt(function() {
//...
});
and implementation runIt: function runIt() {
// do something with pass
cscan： I have a Java constructor that takes a functional interface as a parameter: public ConsumerService(QueueName queue, Consumer<T> function) {
super(queue);
this.function = function;
}
I am trying to use this constructor in Scala, but the compiler
scanning I have a Java constructor that takes a functional interface as a parameter: public ConsumerService(QueueName queue, Consumer<T> function) {
super(queue);
this.function = function;
}
I am trying to use this constructor in Scala, but the compil
scanning I have a Java constructor that takes a functional interface as a parameter: public ConsumerService(QueueName queue, Consumer<T> function) {
super(queue);
this.function = function;
}
I am trying to use this constructor in Scala, but the compil
cscan： I have a Java constructor that takes a functional interface as a parameter: public ConsumerService(QueueName queue, Consumer<T> function) {
super(queue);
this.function = function;
}
I am trying to use this constructor in Scala, but the compiler
sphygmomanometer I want to use a PHP interface like Java interface. How can I make this work in PHP? Android （Java ： ： btnDownload.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
//------------------
sphygmomanometer I want to use a PHP interface like Java interface. How can I make this work in PHP? Android （Java） ： btnDownload.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
//-------------------
sphygmomanometer I want to use a PHP interface like Java interface. How can I make this work in PHP? Android （Java ： ： btnDownload.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
//------------------
Paul Redmond I want to use an interface to set data types and then call them in a function while setting default values without passing the data . I am getting the after canvas error ',' expected.in the function . Can't I call it that? // Options
interface opt
Paul Redmond I want to use an interface to set data types and then call them in a function while setting default values without passing the data . I am getting the after canvas error ',' expected.in the function . Can't I call it that? // Options
interface opt
Paul Redmond I want to use an interface to set data types and then call them in a function while setting default values without passing the data . I am getting the after canvas error ',' expected.in the function . Can't I call it that? // Options
interface opt
Oleg_Korchickiy How to pass function as parameter in Javascript interface, save as string and then call? For example, I describe Javascript Interface: class JSInterface{
String myFunction;
//set function into myFunction attribute
@JavascriptInterface
Paul Redmond I want to use an interface to set data types and then call them in a function while setting default values without passing the data . I am getting the after canvas error ',' expected.in the function . Can't I call it that? // Options
interface opt
Paul Redmond I want to use an interface to set data types and then call them in a function while setting default values without passing the data . I am getting the after canvas error ',' expected.in the function . Can't I call it that? // Options
interface opt
username I am a beginner trying to learn PHP. I created a class called Image (in a file called image.php) that contains some basic functionality. I'd like to be able to create a "new" image object on the hard drive associated with the jpeg and then pass that f
username I am a beginner trying to learn PHP. I created a class called Image (in a file called image.php) that contains some basic functionality. I'd like to be able to create a "new" image object on the hard drive associated with the jpeg and then pass that f
Ashok Puddle I have a function. It has method chaining that needs to be executed. public function someFunction()
{
$query=$this->model;
$query->select($columns)
->skip($request->get('start') * $request->get('length'))
->take($reques
Ashok Puddle I have a function. It has method chaining that needs to be executed. public function someFunction()
{
$query=$this->model;
$query->select($columns)
->skip($request->get('start') * $request->get('length'))
->take($reques
permethrin I want to pass variadic function arguments to one function and foothen foovariadic function arguments to another function bar. At the same time, the initial caller should also be able to call directly barwith variadic function arguments . How can I
Zby Sheikh I want to pass a function (not the result) as an argument to another function. Suppose I have function double_fn($fn)
I want to run a given function ($fn) twice. Is there such a mechanism in PHP? I know you are a kind of variable in a python functi
Centers for Disease Control and Prevention I have two functions - the first is complex, it takes about 15 seconds to load when it gets data from a 3rd party. The second is normal functionality. To illustrate this is what I have <?php
class ComplexFunctions{
p
Zby Sheikh I want to pass a function (not the result) as an argument to another function. Suppose I have function double_fn($fn)
I want to run a given function ($fn) twice. Is there such a mechanism in PHP? I know you are a kind of variable in a python functi
Mostafa: I implemented an object generator that takes a class name and tries to create a new instance object. The builder will try to inject the service if needed. The class name is passed as a string in the current implementation. Here is an example $classNam