Related
Ryan Haining I know the standard has an exception for extending the lifetime of temporary objects, which basically says that binding a const reference in a constructor doesn't extend the lifetime, but does that apply to literals as well? E.g: class C {
pri
Paul Redmond I want to use an interface to set data types and then call them in a function while setting default values without passing the data . I am getting the after canvas error ',' expected.in the function . Can't I call it that? // Options
interface opt
username With the latest Delphi version (Berlin/10.1/24), is the [Ref] attribute really necessary? I'm asking this because the online documentation says: Constant parameters can be passed to functions by value or by reference, depending on the specific compile
Thomas B. Suppose you have a set of pointers (yes...): std::set<SomeType*> myTypeContainer;
Then suppose you want to search this collection from a const method of SomeType: bool SomeType::IsContainered() const
{
return myTypeContainer.find(this) != myType
use The following code compiles fine . #include <iostream>
struct rgb8{
uint8_t r() const {return 0;};
};
template<typename L, typename P>
L pixelToLevel(P p) {
return static_cast<L>(p);
}
template<>
uint8_t pixelToLevel<uint8_t, rgb8>(rgb8 p) { /
Ryan Haining I know the standard has an exception for extending the lifetime of temporary objects, which basically says that binding a const reference in a constructor doesn't extend the lifetime, but does that apply to literals as well? E.g: class C {
pri
Dean Why does the following work? #include <iostream>
using namespace std;
class PolyLine {
public:
PolyLine() = default;
PolyLine(PolyLine * ptr) {
std::cout << "Ctor called" << std::endl;
}
};
void function(const PolyLine& pt) {
}
int main() {
username With the latest Delphi version (Berlin/10.1/24), is the [Ref] attribute really necessary? I'm asking this because the online documentation says: Constant parameters can be passed to functions by value or by reference, depending on the specific compile
innocent bystander Imagine the following simplified code: #include <iostream>
void foo(const int& x) { do_something_with(x); }
int main() { foo(42); return 0; }
(1) Besides optimization, what happens when 42 is passed to foo? Does the compiler stick 42 somew
innocent bystander Imagine the following simplified code: #include <iostream>
void foo(const int& x) { do_something_with(x); }
int main() { foo(42); return 0; }
(1) Besides optimization, what happens when 42 is passed to foo? Does the compiler stick 42 somew
Thomas B. Suppose you have a set of pointers (yes...): std::set<SomeType*> myTypeContainer;
Then suppose you want to search this collection from a const method of SomeType: bool SomeType::IsContainered() const
{
return myTypeContainer.find(this) != myType
username With the latest Delphi version (Berlin/10.1/24), is the [Ref] attribute really necessary? I'm asking this because the online documentation says: Constant parameters can be passed to functions by value or by reference, depending on the specific compile
Paul Redmond I want to use an interface to set data types and then call them in a function while setting default values without passing the data . I am getting the after canvas error ',' expected.in the function . Can't I call it that? // Options
interface opt
Paul Redmond I want to use an interface to set data types and then call them in a function while setting default values without passing the data . I am getting the after canvas error ',' expected.in the function . Can't I call it that? // Options
interface opt
use The following code compiles fine . #include <iostream>
struct rgb8{
uint8_t r() const {return 0;};
};
template<typename L, typename P>
L pixelToLevel(P p) {
return static_cast<L>(p);
}
template<>
uint8_t pixelToLevel<uint8_t, rgb8>(rgb8 p) { /
Barry In short, is it better to pass pointers by value or const reference? I wrote a simple function to explore: void foo(int* v) { std::cout << *v << endl; }
and void foo(int* const& v) { std::cout << *v << endl; }
I tried looking at the generated assembly,
Dan Clemenko I have the following C++ code (just an example of a simple problem) #include <iostream>
#include <string>
#include <vector>
double get_first(const std::vector<double>& vec) {
return vec[0];
}
int main()
{
std::vector<double> some_vec = {1,
some development Suppose I have the following schema for later use $ref: "schemas": {
"Order": {
"type": "object",
"properties": {
"id": {
"type": "integer",
"format": "int64"
},
"petI
Cheeseman 69 Here is structwhat I have: typedef struct
{
float r, g, b;
} color_t;
I want to pass a compound literal of this structas a parameter to a function like this: void printcolor(color_t c)
{
printf("color is : %f %f %f\n", c.r, c.g, c.b);
}
use The following code compiles fine . #include <iostream>
struct rgb8{
uint8_t r() const {return 0;};
};
template<typename L, typename P>
L pixelToLevel(P p) {
return static_cast<L>(p);
}
template<>
uint8_t pixelToLevel<uint8_t, rgb8>(rgb8 p) { /
Ryan Haining I know the standard has an exception for extending the lifetime of temporary objects, which basically says that binding a const reference in a constructor doesn't extend the lifetime, but does that apply to literals as well? E.g: class C {
pri
username With the latest Delphi version (Berlin/10.1/24), is the [Ref] attribute really necessary? I'm asking this because the online documentation says: Constant parameters can be passed to functions by value or by reference, depending on the specific compile
username With the latest Delphi version (Berlin/10.1/24), is the [Ref] attribute really necessary? I'm asking this because the online documentation says: Constant parameters can be passed to functions by value or by reference, depending on the specific compile
innocent bystander Imagine the following simplified code: #include <iostream>
void foo(const int& x) { do_something_with(x); }
int main() { foo(42); return 0; }
(1) Besides optimization, what happens when 42 is passed to foo? Does the compiler stick 42 somew
innocent bystander Imagine the following simplified code: #include <iostream>
void foo(const int& x) { do_something_with(x); }
int main() { foo(42); return 0; }
(1) Besides optimization, what happens when 42 is passed to foo? Does the compiler stick 42 somew
Thomas B. Suppose you have a set of pointers (yes...): std::set<SomeType*> myTypeContainer;
Then suppose you want to search this collection from a const method of SomeType: bool SomeType::IsContainered() const
{
return myTypeContainer.find(this) != myType
some development Suppose I have the following schema for later use $ref: "schemas": {
"Order": {
"type": "object",
"properties": {
"id": {
"type": "integer",
"format": "int64"
},
"petI
use The following code compiles fine . #include <iostream>
struct rgb8{
uint8_t r() const {return 0;};
};
template<typename L, typename P>
L pixelToLevel(P p) {
return static_cast<L>(p);
}
template<>
uint8_t pixelToLevel<uint8_t, rgb8>(rgb8 p) { /
Mr. Sha The tlb library in my python project passes win32com.client. I've easily used a number of built-in functions, but one of the main functions takes a list of arguments for two of them marked as ref int. When I try to pass a python integer to the function