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范 Taro I have this url:https://uk.soccerway.com/national/italy/serie-a/20172018/regular-season/r42011/?ICID=TN_02_01_02 I want to remove ?ICID=TN_02_01_02because this string is dynamic so I can't use .Replace()method, any ideas? Bryce Meister Using Uri try to
Jim Williams Here's an example of a URL from which I'm extracting the last part, which is the person's name. yourdomain.com/?n=PERSON .
i want a part " ?n= "
Then use this person's name on the same HTML page. So I'll display the person's name on the web p
Jim Williams Here's an example of a URL from which I'm extracting the last part, which is the person's name. yourdomain.com/?n=PERSON .
i want a part " ?n= "
Then use this person's name on the same HTML page. So I'll display the person's name on the web p
Nithinkumar CN $url = explode('/', $articleimage);
$articleurl = array_pop($url);
I have used the above method to get the last part of the URL and it works, but I want to remove the last part from the URL and show the rest, please help me, here I am mention
Valentine P Currently, I have a url that looks like: www.mywebsite.com/confirm/ZChCQhXNJ5i The last part of the URL is a random string. I want to remove it from my url to get something like www.mywebsite.com/confirm I've tried many things, eg, RewriteRule ^(co
Nithinkumar CN $url = explode('/', $articleimage);
$articleurl = array_pop($url);
I have used the above method to get the last part of the URL and it works, but I want to remove the last part from the URL and show the rest, please help me, here I am mention
Valentine P Currently, I have a url that looks like: www.mywebsite.com/confirm/ZChCQhXNJ5i The last part of the URL is a random string. I want to remove it from my url to get something like www.mywebsite.com/confirm I've tried many things, eg, RewriteRule ^(co
Nithinkumar CN $url = explode('/', $articleimage);
$articleurl = array_pop($url);
I have used the above method to get the last part of the URL and it works, but I want to remove the last part from the URL and show the rest, please help me, here I am mention
Nithinkumar CN $url = explode('/', $articleimage);
$articleurl = array_pop($url);
I have used the above method to get the last part of the URL and it works, but I want to remove the last part from the URL and show the rest, please help me, here I am mention
Valentine P Currently, I have a url that looks like: www.mywebsite.com/confirm/ZChCQhXNJ5i The last part of the URL is a random string. I want to remove it from my url to get something like www.mywebsite.com/confirm I've tried many things, eg, RewriteRule ^(co
Valentine P Currently, I have a url that looks like: www.mywebsite.com/confirm/ZChCQhXNJ5i The last part of the URL is a random string. I want to remove it from my url to get something like www.mywebsite.com/confirm I've tried many things, eg, RewriteRule ^(co
Aquatic 7 I have some urls that look like this: https://lh5.googleusercontent.com/-Ilxb2a99p6E/AAAAAAAAAAI/AAAAAAAAAAA/AMZuucn9e4iS4IbCmDPR7UcPlz31VlV6dw/s96-c/photo.jpg This gives a 96x96 resized picture. If you delete "s96-c" and after, the original picture
resume To put it another way - I want to use Bash command substitution and string substitution in the same line. My actual command is longer, but the ridiculous use of echo here is just an "alternative" to shorten it, and behaves the same - with the same error
resume To put it another way - I want to use Bash command substitution and string substitution in the same line. My actual command is longer, but the ridiculous use of echo here is just an "alternative" to shorten it, and behaves the same - with the same error
resume To put it another way - I want to use Bash command substitution and string substitution in the same line. My actual command is longer, but the ridiculous use of echo here is just an "alternative" to shorten it, and behaves the same - with the same error
resume To put it another way - I want to use Bash command substitution and string substitution in the same line. My actual command is longer, but the ridiculous use of echo here is just an "alternative" to shorten it, and behaves the same - with the same error
resume To put it another way - I want to use Bash command substitution and string substitution in the same line. My actual command is longer, but the ridiculous use of echo here is just an "alternative" to shorten it, and behaves the same - with the same error
Crab Nebula For my work, I have to download a lot of images, some of them have ".weblp" file extension. Basically, I go to a site and open different images in different tabs. Many of them follow the format: https://example/example.jpg.webp
I just want to remo
Crab Nebula For my work, I have to download a lot of images, some of them have ".weblp" file extension. Basically, I go to a site and open different images in different tabs. Many of them follow the format: https://example/example.jpg.webp
I just want to remo
Crab Nebula For my work, I have to download a lot of images, some of them have ".weblp" file extension. Basically, I go to a site and open different images in different tabs. Many of them follow the format: https://example/example.jpg.webp
I just want to remo
Crab Nebula For my work, I have to download a lot of images, some of them have ".weblp" file extension. Basically, I go to a site and open different images in different tabs. Many of them follow the format: https://example/example.jpg.webp
I just want to remo
Crab Nebula For my work, I have to download a lot of images, some of them have ".weblp" file extension. Basically, I go to a site and open different images in different tabs. Many of them follow the format: https://example/example.jpg.webp
I just want to remo
Crab Nebula For my work, I have to download a lot of images, some of them have ".weblp" file extension. Basically, I go to a site and open different images in different tabs. Many of them follow the format: https://example/example.jpg.webp
I just want to remo
user enter code hereI have the following url (part of it). where i need to get the details after the final "/" /magasins/vos-magasins/le-bhv-marais
/magasins/vos-magasins/le-bhv-marais-homme
/magasins/vos-magasins/bhv-marais-parly2
/magasins/le-bhv-marais-la-n
user enter code hereI have the following url (part of it). where i need to get the details after the final "/" /magasins/vos-magasins/le-bhv-marais
/magasins/vos-magasins/le-bhv-marais-homme
/magasins/vos-magasins/bhv-marais-parly2
/magasins/le-bhv-marais-la-n
Kairos I've written a REST api in Java and a turn-based online client game that uses the api. When a player creates a new game instance, other players can join via the URL given the game ID. So say Player1 creates a new game instance from the page www.mysite.c
Thomas Huangism I am trying to remove CSS stylesheets using JS/jQuery. I know it will be in the 'head' element and contain the text: civicrm.css, but I don't know the rest of the URL. Is that so? if $("head:contains('civicrm.css')") {
remove the entire link i
Thomas Huangism I am trying to remove CSS stylesheets using JS/jQuery. I know it will be in the 'head' element and contain the text: civicrm.css, but I don't know the rest of the URL. Is that so? if $("head:contains('civicrm.css')") {
remove the entire link i
Akash Tripuramallu） I have an image: original image I want to remove the grey grid part of the image without affecting the rest of the image i.e. the part inside the black circle. I have written a code for this import cv2
import numpy as np
from PIL import Ima