How do I get 4 bits from a 16 bit data?

Sajal Singh:

I use the getShort() method of the byte buffer to get my short value, I convert it to an int and print the binary value, which is a 16-bit data and I need to access from that 16-bit data 4-bit int value.

short bitRateShort = buf.getShort(32 + 2);
int bitRateInteger = Short.toUnsignedInt(bitRateShort);
System.out.println(bitRateInteger);//46144
System.out.println(Integer.toBinaryString(bitRateInteger));// 1011010001000000

I need to start with an integer value where 4 bits in my case are 1011, how can I mask these 16 bits to get 4 bits nibble?

AVI：

try this:

int bitRateInteger = 46144;
System.out.println(Integer.toBinaryString(bitRateInteger&0xF000));
System.out.println(Integer.toBinaryString((bitRateInteger&0xF000)>>12));

output:

1011000000000000
1011

First, we mask the starting 4 bits with bitmask 0xF000 (binary 0b1111_0000_0000_0000). Then we shift right by the bits we get by 12, getting rid of the "known" zeros at the end.

EDIT: As @CarlosHeuberger very kindly pointed out, you don't even need to do that &, since >>all right-hand bits are truncated by default. Well, do this instead:

int bitRateInteger = 46144;
System.out.println(Integer.toBinaryString(bitRateInteger>>12));

output:

1011

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