How do I enter the results of a shell command line line by line?

must

I am learning shell scripting. I want to check the size of directories (and files). I made a sample script

#!/bin/bash

for dir in $(du ".")
do
  echo "dir = $dir"
  read T_SIZE T_PATH <<< $dir
  echo "T_SIZE = $T_SIZE"
  echo "T_PATH = $T_PATH"
done

The directory structure under the current directory has only one directory "a".

The result is

dir = 4
T_SIZE = 4
T_PATH = 
dir = ./a
T_SIZE = ./a
T_PATH = 
dir = 16
T_SIZE = 16
T_PATH = 
dir = .
T_SIZE = .
T_PATH =

It seems that the command "du" gives the result verbatim. However, I want the command "du" to give the result line by line, and I want the result of the script above to be

dir = 4
T_SIZE = 4
T_PATH = ./a
dir = 16
T_SIZE = 16
T_PATH = .

Please tell me any questions or suggestions for me.

thank you very much.

John 1024

To read the output of a command duline by line , try:

du . | while read size path
do
   echo "size=$size path=$path"
done

Alternatively, if the shell used (like bash) supports process substitution:

while read size path
do
   echo "size=$size path=$path"
done < <(du ".")

There is a big difference between the two methods. In the first whileexample above, the loop is running in a subshell, so when the subshell finishes, all its shell variable variables will disappear. In the code behind , the shell variable is still available after the whileloop completes .

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