Related
Kedour I have come across symbols like this: int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}();
Can you explain this statement? I'm a C++03 user and recently upgraded to C++11. As of today, I started using C++14 and came across t
Martin Mozart I capture unique_ptr in lambda expression this way: auto str = make_unique<string>("my string");
auto lambda = [ capturedStr = std::move(str) ] {
cout << *capturedStr.get() << endl;
};
lambda();
It worked fine until I tried to move capturedSt
and h I'm currently reading several books to learn about c++14 features. I'm trying to bind parameters to a function using variadic templates. I know how to use std::bind to do this, but I would also like to use c++14 lambda expressions to do this, just out of
Martin Mozart I capture unique_ptr in lambda expression this way: auto str = make_unique<string>("my string");
auto lambda = [ capturedStr = std::move(str) ] {
cout << *capturedStr.get() << endl;
};
lambda();
It worked fine until I tried to move capturedSt
Blair Davidson I'm trying to understand/clarify the code generated when passing captures to lambdas, especially in the generalized init captures added in C++14. Given the following code samples listed below, this is my current understanding of what the compile
username Why update the value x to 6 and initialize y to 7? Can someone give me some clues? int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}(); // Updates ::x to 6, and initializes y to 7.
Tzu Chi In a cap
username Why update the value x to 6 and initialize y to 7? Can someone give me some clues? int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}(); // Updates ::x to 6, and initializes y to 7.
Tzu Chi In a cap
Enrico On pages 227-228 of Item 32 from Effective Modern C++, Scott Meyers proposes the following code block to address the lack of generic lambda captures in C++11 . // data is in scope
auto func =
std::bind(
[](const std::vector<double>& x) // I've r
Enrico On pages 227-228 of Item 32 from Effective Modern C++, Scott Meyers proposes the following code block to address the lack of generic lambda captures in C++11 . // data is in scope
auto func =
std::bind(
[](const std::vector<double>& x) // I've r
and h I'm currently reading several books to learn about c++14 features. I'm trying to bind parameters to a function using variadic templates. I know how to use std::bind to do this, but I would also like to use c++14 lambda expressions to do this, just out of
username Why update the value x to 6 and initialize y to 7? Can someone give me some clues? int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}(); // Updates ::x to 6, and initializes y to 7.
Tzu Chi In a cap
Martin Mozart I capture unique_ptr in lambda expression this way: auto str = make_unique<string>("my string");
auto lambda = [ capturedStr = std::move(str) ] {
cout << *capturedStr.get() << endl;
};
lambda();
It worked fine until I tried to move capturedSt
and h I'm currently reading several books to learn about c++14 features. I'm trying to bind parameters to a function using variadic templates. I know how to use std::bind to do this, but I would also like to use c++14 lambda expressions to do this, just out of
Kedour I have come across symbols like this: int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}();
Can you explain this statement? I'm a C++03 user and recently upgraded to C++11. As of today, I started using C++14 and came across t
Blair Davidson I'm trying to understand/clarify the code generated when passing captures to lambdas, especially in the generalized init captures added in C++14. Given the following code samples listed below, this is my current understanding of what the compile
username Why update the value x to 6 and initialize y to 7? Can someone give me some clues? int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}(); // Updates ::x to 6, and initializes y to 7.
Tzu Chi In a cap
Enrico On pages 227-228 of Item 32 from Effective Modern C++, Scott Meyers proposes the following code block to address the lack of generic lambda captures in C++11 . // data is in scope
auto func =
std::bind(
[](const std::vector<double>& x) // I've r
Kedour I have come across symbols like this: int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}();
Can you explain this statement? I'm a C++03 user and recently upgraded to C++11. As of today, I started using C++14 and came across t
Martin Mozart I capture unique_ptr in lambda expression this way: auto str = make_unique<string>("my string");
auto lambda = [ capturedStr = std::move(str) ] {
cout << *capturedStr.get() << endl;
};
lambda();
It worked fine until I tried to move capturedSt
Blair Davidson I'm trying to understand/clarify the code generated when passing captures to lambdas, especially in the generalized init captures added in C++14. Given the following code samples listed below, this is my current understanding of what the compile
username Why update the value x to 6 and initialize y to 7? Can someone give me some clues? int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}(); // Updates ::x to 6, and initializes y to 7.
Tzu Chi In a cap
username Why update the value x to 6 and initialize y to 7? Can someone give me some clues? int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}(); // Updates ::x to 6, and initializes y to 7.
Tzu Chi In a cap
Martin Mozart I capture unique_ptr in lambda expression this way: auto str = make_unique<string>("my string");
auto lambda = [ capturedStr = std::move(str) ] {
cout << *capturedStr.get() << endl;
};
lambda();
It worked fine until I tried to move capturedSt
and h I'm currently reading several books to learn about c++14 features. I'm trying to bind parameters to a function using variadic templates. I know how to use std::bind to do this, but I would also like to use c++14 lambda expressions to do this, just out of
and h I'm currently reading several books to learn about c++14 features. I'm trying to bind parameters to a function using variadic templates. I know how to use std::bind to do this, but I would also like to use c++14 lambda expressions to do this, just out of
Blair Davidson I'm trying to understand/clarify the code generated when passing captures to lambdas, especially in the generalized init captures added in C++14. Given the following code samples listed below, this is my current understanding of what the compile
Blair Davidson I'm trying to understand/clarify the code generated when passing captures to lambdas, especially in the generalized init captures added in C++14. Given the following code samples listed below, this is my current understanding of what the compile
username Why update the value x to 6 and initialize y to 7? Can someone give me some clues? int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}(); // Updates ::x to 6, and initializes y to 7.
Tzu Chi In a cap
username Why update the value x to 6 and initialize y to 7? Can someone give me some clues? int x = 4;
auto y = [&r = x, x = x+1]()->int {
r += 2;
return x+2;
}(); // Updates ::x to 6, and initializes y to 7.
Tzu Chi In a cap