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Rafflesia class Student{
public:
Student();
Student(string name, int score);
string getName();
int getScore();
void insert(string name, int score);
friend ostream& operator<<(ostream& os, const Student& student){
os << "Name: "<
Rafflesia class Student{
public:
Student();
Student(string name, int score);
string getName();
int getScore();
void insert(string name, int score);
friend ostream& operator<<(ostream& os, const Student& student){
os << "Name: "<
Movie import React, { Component } from 'react';
import { AppRegistry, Alert, FlatList, StyleSheet, Text, View } from 'react-native';
export default class FlatListBasics extends Component {
_onscroll() {
this.flatList.scrollToEnd( { animated: false } )
Movie import React, { Component } from 'react';
import { AppRegistry, Alert, FlatList, StyleSheet, Text, View } from 'react-native';
export default class FlatListBasics extends Component {
_onscroll() {
this.flatList.scrollToEnd( { animated: false } )
Roberto Rocco In the book I'm working on, it says that if a vector is passed to a function, the name of the vector is always treated as a pointer. Actually it is. But I don't understand why in the first function the compiler allows a const clause, but in the s
Roberto Rocco In the book I'm working on, it says that if a vector is passed to a function, the name of the vector is always treated as a pointer. Actually it is. But I don't understand why in the first function the compiler allows a const clause, but in the s
Roberto Rocco In the book I'm working on, it says that if a vector is passed to a function, the name of the vector is always treated as a pointer. Actually it is. But I don't understand why in the first function the compiler allows a const clause, but in the s
Roberto Rocco In the book I'm working on, it says that if a vector is passed to a function, the name of the vector is always treated as a pointer. Actually it is. But I don't understand why in the first function the compiler allows a const clause, but in the s
Roberto Rocco In the book I'm working on, it says that if a vector is passed to a function, the name of the vector is always treated as a pointer. Actually it is. But I don't understand why in the first function the compiler allows a const clause, but in the s
i work for buck I'm trying to create a vector factory that creates a vector of values 1with a specified size , sbut it's not working. template<size_t s>
constexpr std::vector<int>& vector_factory()
{
std::vector<int> v(s, 1);
return v;
}
int main(int
i work for buck I'm trying to create a vector factory that creates a vector of values 1with a specified size , sbut it's not working. template<size_t s>
constexpr std::vector<int>& vector_factory()
{
std::vector<int> v(s, 1);
return v;
}
int main(int
gstackoverflow I have the following code snippet: int i = 5l; // not valid (compile error)
byte b = 5; // valid
What do you think about this? Why? Assyria This is defined in JLS #5.2 (Assignment Transformation) : If the expression is a constant expression (§1
Roberto Rocco I am trying to protect the -a-array of my_sum_array function from changes. In the function block, I didn't make any changes to -a-, but I have a warning (WARNING: Assigning from 'const int *' to 'int *' discards qualifiers [-Wincompatible-pointer
Roberto Rocco I am trying to protect the -a-array of my_sum_array function from changes. In the function block, I didn't make any changes to -a-, but I have a warning (WARNING: Assigning from 'const int *' to 'int *' discards qualifiers [-Wincompatible-pointer
Roberto Rocco I am trying to protect the -a-array of my_sum_array function from changes. In the function block, I didn't make any changes to -a-, but I have a warning (WARNING: Assigning from 'const int *' to 'int *' discards qualifiers [-Wincompatible-pointer
Roberto Rocco I am trying to protect the -a-array of my_sum_array function from changes. In the function block, I didn't make any changes to -a-, but I have a warning (WARNING: Assigning from 'const int *' to 'int *' discards qualifiers [-Wincompatible-pointer
Roberto Rocco I am trying to protect the -a-array of my_sum_array function from changes. In the function block, I didn't make any changes to -a-, but I have a warning (WARNING: Assigning from 'const int *' to 'int *' discards qualifiers [-Wincompatible-pointer
seasonal shot I am trying to understand const in C++ . I wrote the following code snippet: const int x=5;
int *ptr;
ptr=(int*)&x;
cout<<"address of x="<<&x<<endl;
cout<<"value of ptr="<<ptr<<endl;
*ptr=11;
cout<<"*ptr="<<*ptr<<endl;
cout<<"x="<<x;
the output
seasonal shot I am trying to understand const in C++ . I wrote the following code snippet: const int x=5;
int *ptr;
ptr=(int*)&x;
cout<<"address of x="<<&x<<endl;
cout<<"value of ptr="<<ptr<<endl;
*ptr=11;
cout<<"*ptr="<<*ptr<<endl;
cout<<"x="<<x;
the output
Matt Johnson My program requires the user to provide an integer, so I'm trying to create a loop that if they enter a non-integer, the loop doesn't end until an integer is entered. I tried: PlayerCount = input("How many players?")
while PlayerCount != int:
Matt Johnson My program requires the user to provide an integer, so I'm trying to create a loop that if they enter a non-integer, the loop doesn't end until an integer is entered. I tried: PlayerCount = input("How many players?")
while PlayerCount != int:
BanksySan： The following quote returns an example from what's new in C# 7.0 : public ref int Find(int number, int[] numbers)
{
for (int i = 0; i < numbers.Length; i++)
{
if (numbers[i] == number)
{
return ref numbers[i]; //
BanksySan： The following quote returns an example from what's new in C# 7.0 : public ref int Find(int number, int[] numbers)
{
for (int i = 0; i < numbers.Length; i++)
{
if (numbers[i] == number)
{
return ref numbers[i]; //
tailor public func +<T: CustomStringConvertible>(lhs: T, rhs: T)->String{
return lhs.description+rhs.description
}
let a:String = "A"
let i:Int = 0
print(a+i)
I am overloading the '+' operator for the CustomStringConvertible type. Both String and Int c
tailor public func +<T: CustomStringConvertible>(lhs: T, rhs: T)->String{
return lhs.description+rhs.description
}
let a:String = "A"
let i:Int = 0
print(a+i)
I am overloading the '+' operator for the CustomStringConvertible type. Both String and Int c
Winter Actually, my task is as simple as trying to find the index of the first blank cell. But my question is why the ISBLANKreturn array doesn't work with the MATCHfunction, I think it should work. So I guess below is what I don't know. Here is the first vers
John Criss I've been trying to understand the following this morning, and was hoping someone could give a good explanation of why this approach doesn't work. I gave an example to LinqPadillustrate my problem: void Main()
{
var myPeople = new People();
myPe
John Criss I've been trying to understand the following this morning, and was hoping someone could give a good explanation of why this approach doesn't work. I gave an example to LinqPadillustrate my problem: void Main()
{
var myPeople = new People();
myPe
Stewart I had variables "ballX" and "ballY" before. However, when I try to use console.log to view their values, they now show as "undefined", so I must be messing with them. I've spent 2-3 hours going through my code and looking online for fixes to no avail,